Rakesh Kumar

If there is a symbol in a string that we are going to print or use further in a perl program but when we execute it the interpreter or compiler is not getting correct meaning of that string . In this condition compiler gives a error ‘Missing operator before’ ”your symbol “. A bareword is series of characters outside of a string that PERL doesn’t recognize. We can also take a example to understand the mean of bareword #!/usr/bin/perl use warnings; print  255 , “\n”; print  0377 , “\n”; print   0b11111111, “\n”; print  0xFF , “\n”; The output of each print statement is 255 255 255 255 But if we turn the code of above program as :- #!/usr/bin/perl use warnings; print  0378 , “\n”; print   0b11111112, “\n”; print  0xFG , “\n”; Illegal octal digit ‘8’ at line 3 , at the end of line. Illegal binary digit ‘2’ at line 4 , at the end of line. Bareword found where operator expected at line 5 , near “0xfG” (Missing operator before G)...