What are Barewords and how they disturb a PERL program execution?

If there is a symbol in a string that we are going to print or use further in a perl program but when we execute it the interpreter or compiler is not getting correct meaning of that string . In this condition compiler gives a error ‘Missing operator before’ ”your symbol “.
A bareword is series of characters outside of a string that PERL doesn’t recognize.
We can also take a example to understand the mean of bareword

#!/usr/bin/perl
use warnings;
print  255 , “\n”;
print  0377 , “\n”;
print   0b11111111, “\n”;
print  0xFF , “\n”;

The output of each print statement is
255
255
255
255

But if we turn the code of above program as :-

#!/usr/bin/perl
use warnings;
print  0378 , “\n”;
print   0b11111112, “\n”;
print  0xFG , “\n”;

Illegal octal digit ‘8’ at line 3 , at the end of line.
Illegal binary digit ‘2’ at line 4 , at the end of line.
Bareword found where operator expected at line 5 , near “0xfG”
(Missing operator before G)
Syntax error at line at line 5 , near “0xfG”.